Wednesday 4 January 2017

Remainder Theorem
and Factor Theorem

Or: how to avoid Polynomial Long Division when finding factors
Do you remember doing division in Arithmetic?
remainder-7-2
"7 divided by 2 equals 3 with a remainder of 1"
Each part of the division has names:
remainder-7-2
Which can be rewritten as a sum like this:
7 = 2 times 3 + 1

Polynomials

Well, we can also divide polynomials.
f(x) ÷ g(x) = q(x) with a remainder of r(x)
But it is better to write it as a sum like this:
f(x) = g(x) times q(x) + r(x)
Like in this example using Polynomial Long Division:

Example: 2x2-5x-1 divided by x-3

  • f(x) is 2x2-5x-1
  • g(x) is x-3
polynomial long division
After dividing we get the answer 2x+1, but there is a remainder of 2.
  • q(x) is 2x+1
  • r(x) is 2
In the style f(x) = g(x)·q(x) + r(x) we can write:
2x2-5x-1 = (x-3)(2x+1) + 2
https://www.mathsisfun.com/algebra/polynomials-remainder-factor.html

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